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Urdhva Tiryagbhyam: Multiply Any Two Numbers

✍️ Ishita Parikh 📅 20 August 2026 ⏱ 11 min read Vedic Maths

Most Vedic Maths you meet online comes with conditions. Multiply numbers near 100. Square a number ending in 5. Impressive when the numbers cooperate, useless when they do not, which is most of the time.

Urdhva Tiryagbhyam is the exception. It multiplies any two numbers, and it is the reason the system is worth learning at all rather than collecting party tricks. The name means vertically and crosswise, and once you can see the pattern it is genuinely faster than the long multiplication you were taught at school.

The idea in one sentence

Long multiplication writes a row for each digit and adds the rows at the end. This produces the digits of the answer directly, one at a time, right to left, with nothing to add up afterwards.

That is the whole advantage. No rows means no paper, and no addition at the end means one less place to make a mistake.

Two digits by two digits: three steps

Take 23 × 41.

Step 1, right column. Multiply the two right-hand digits.

3 × 1 = 3     last digit of the answer

Step 2, crosswise. Multiply each digit by the other number's opposite digit, and add.

(2 × 1) + (3 × 4) = 2 + 12 = 14     write 4, carry 1

Step 3, left column. Multiply the two left-hand digits, add the carry.

2 × 4 = 8, plus the carried 1 = 9

Reading the digits back: 943.

Check it the long way if you like. 23 × 41 = 943. It is right, and it took three small multiplications instead of two rows and an addition.

Why "crosswise" is the whole trick

The middle step is where the method earns its name, and it is the only part people get wrong. You are not multiplying the two middle digits. You are making two products by crossing over, and adding them.

The reason is place value. In 23 × 41, the tens column of the answer collects the 20 × 1 and the 3 × 40. Both land in the tens. Long multiplication collects them in separate rows and adds later; this collects them on the spot.

Now with carries, which is where it gets real

Clean examples teach nothing. Take 68 × 74, where every step carries.

  1. Right: 8 × 4 = 32. Write 2, carry 3.
  2. Crosswise: (6 × 4) + (8 × 7) = 24 + 56 = 80. Add the carried 3 to get 83. Write 3, carry 8.
  3. Left: 6 × 7 = 42. Add the carried 8 to get 50.

Answer: 5032. And 68 × 74 really is 5032.

Notice the carry out of step two was 8, not 1. Carries here are not limited to a single unit the way they are in addition, and that trips up anyone who learned this from a tidy example. Whatever is left after you write the last digit carries forward, however big it is.

One more, 47 × 62:

  • 7 × 2 = 14 → write 4, carry 1
  • (4 × 2) + (7 × 6) = 8 + 42 = 50, plus 1 = 51 → write 1, carry 5
  • 4 × 6 = 24, plus 5 = 29

Answer: 2914.

Three digits by three digits: five steps

The pattern extends by adding crosswise steps in the middle. Two digits needs three columns, three digits needs five. The shape is a fan: it opens out and closes again.

Take 123 × 456.

Column Products to add Total + carry Write / carry
1st3 × 618write 8, carry 1
2nd(2 × 6) + (3 × 5)27 + 1 = 28write 8, carry 2
3rd(1 × 6) + (2 × 5) + (3 × 4)28 + 2 = 30write 0, carry 3
4th(1 × 5) + (2 × 4)13 + 3 = 16write 6, carry 1
5th1 × 44 + 1 = 5write 5

Reading upward: 56088. And 123 × 456 = 56,088.

The middle column is the widest, with three products. That is the fan at its fullest, and it is the limit of what most people can hold mentally. Beyond three digits this is still correct and still works, but it stops being a mental method and becomes a written one.

When the two numbers are different lengths

Pad the shorter one with a leading zero. That is all.

214 × 32 becomes 214 × 032, and you run the five-step pattern exactly as above. The zero contributes nothing to the products it appears in, which is precisely why it is safe to add.

Working through: 8, then 14, then 7 plus carry, then 6, then 0. That gives 06848, and a leading zero is just a leading zero: 6848.

Beginners often try to invent a special rule for mismatched lengths. There isn't one, and inventing one is the most common way to go wrong here.

Check it in five seconds

A method that produces an answer with no rows to inspect also gives you nothing to look back over. So check it a different way.

For 68 × 74 = 5032: the digit sum of 68 is 5, of 74 is 2, and 5 × 2 = 10, which reduces to 1. The digit sum of 5032 is 5 + 0 + 3 + 2 = 10, which reduces to 1. They match, so the answer survives the test.

This takes about five seconds and catches most slips. It is not proof, and it is worth knowing exactly what it cannot catch: the digit sum check, and its two blind spots.

What you actually need before starting

Two things, and neither can be worked around.

Tables to nine, fluently. Not recallable with effort. Automatic. Every step asks for two products while you hold a carry, so a pause on 7 × 8 breaks the sequence and you start again.

Confident carrying. The carries here are larger than in addition, sometimes 8 or 9, and they arrive while you are mid-calculation.

A child who is still counting up to reach a table fact will find this frustrating rather than clever. That is not a reason to avoid Vedic Maths, it is a reason to fix the tables first, and there is a proper order for all of this: what order to teach a child.

Where it fits with the other methods

Use Nikhilam when both numbers sit near a base such as 100. It is faster there, because the subtractions are trivial.

Use this everywhere else. It is slower than Nikhilam in Nikhilam's narrow window and it works on everything, which over a whole exam paper matters much more. That is the same conclusion reached in which sutras actually save exam time: the technique that always applies beats the technique that occasionally dazzles.

Where this is taught

Ms. Ishita Parikh holds International Vedic Maths Teachers' Training certification at Grade A from IIVA, approved under Skill India and the NSDC, along with two teaching diplomas for young children.

Classes are live online in small batches, covering all 16 sutras in an order built for the student's age rather than the textbook's. See the Vedic Maths course, or book a free demo class and try this one with someone watching your working, which is the fastest way to find the step you are dropping.

Questions people ask

What is Urdhva Tiryagbhyam?

It is the Vedic Maths method for multiplying any two numbers, and the name means vertically and crosswise. Instead of writing a row for each digit and adding the rows at the end, you produce the answer one digit at a time, right to left, by multiplying pairs of digits vertically and crosswise and carrying as you go. It is the most generally useful technique in the system because, unlike the methods for numbers near 100 or numbers ending in 5, it has no conditions attached.

How do you multiply two two-digit numbers in your head?

Three steps, right to left. Multiply the two right-hand digits for the last digit of the answer. Cross-multiply and add the two products for the middle. Multiply the two left-hand digits for the front. Carry anything above nine into the next step as you go. For 23 times 41 that is 3 times 1 is 3, then 2 times 1 plus 3 times 4 is 14, then 2 times 4 is 8 plus the carried 1 is 9, giving 943. The whole thing holds in your head because you never store more than one running number.

Does vertically and crosswise work for any pair of numbers?

Yes, and that is its real advantage. It has no conditions, unlike Nikhilam which needs numbers close to a base, or the squaring shortcut which needs a number ending in five. It extends to any size by adding more crosswise steps: two digits by two digits takes three steps, three by three takes five. If the two numbers have different lengths, pad the shorter one with a leading zero and proceed exactly as normal.

Is Urdhva Tiryagbhyam actually faster than long multiplication?

For two-digit and three-digit numbers, clearly yes, and mostly because of what it does not do. Long multiplication writes a separate row for each digit and then adds those rows, so it needs paper and it creates a second place to make a mistake. This produces the digits of the answer directly, with nothing to add up at the end. Beyond about four digits the advantage narrows, because you are tracking more crosswise products per column than most people can hold at once.

What should a child know before learning this?

Tables up to nine, fluently, and confident carrying. Those are the two genuine prerequisites and neither can be skipped. The method asks a child to multiply two pairs of digits and add the results while holding a carry, so any hesitation over a single table turns the whole sequence into hard work. A child who still counts up to reach seven times eight will find this frustrating rather than clever, and the honest answer there is to fix the tables first.

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About the Author

Ms. Ishita Parikh is a Sanskrit teacher and Vedic Maths instructor. She holds an MA (Acharya) in Sanskrit from Central Sanskrit University and a three-year Sanskrit diploma from the University of Mumbai, and was awarded the Elite grade in NPTEL's Spoken Sanskrit course at IIT Kharagpur. She is also a trained schoolteacher.

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